How many acres can you mow or work per hour?
Enter working width, actual ground speed and field efficiency. The tool calculates theoretical capacity and then applies time losses. This approach can describe mowing or a farm implement when width and operating speed reflect the actual working pass.
Which width and overlap should you measure?
Enter implement working width and any overlap separately. Effective width is the first minus the overlap. If your width is already measured as effective coverage, leave overlap blank. Applying overlap again would reduce capacity twice.
| Input | Units |
|---|---|
| Implement working width | ft / m |
| Overlap width (optional) | ft / m |
| Operating ground speed in selected unit | as labeled |
| Field efficiency (%) | as labeled |
| Project area (acres, optional) | as labeled |
| Available operating hours (optional) | as labeled |
| Fuel use (L/hour, optional) | as labeled |
| Fuel price per liter (optional) | as labeled |
| Other hourly operating cost (optional) | as labeled |
What is the acres-per-hour formula?
Theoretical capacity equals effective width in feet times speed in miles per hour divided by 8.25. The factor follows 43,560 sq ft per acre divided by 5,280 ft per mile. Multiply that capacity by the field-efficiency fraction for effective acreage per hour.
Theoretical acres/hour = effective width (ft) × speed (mph) ÷ 8.25; effective acres/hour = theoretical capacity × field efficiency/100
Length
What does a ten-foot implement at five mph cover?
With 10 ft effective width and 5 mph work speed, theoretical capacity is 50 ÷ 8.25 = 6.061 acres/hour. At an illustrative 80% field efficiency, effective capacity is about 4.848 acres/hour. The efficiency is an entered scenario, not a machine rating.
Can you enter speed in kilometers per hour?
Yes. Select mph or km/h independently of the dimension units. Width switches between feet and meters. The calculation converts speed and effective width consistently and reports both acres/hour and hectares/hour. A dimension-unit change does not alter the selected speed basis.
What losses belong in field efficiency?
Turning, filling, maneuvering and other nonworking time can reduce effective capacity. Use an observed or project-supported percentage. Overlap is already accounted for in width, so do not apply that same width loss again within the time-efficiency factor.
How long will a measured acreage take?
Enter project acres to divide that area by effective acres/hour. Optional available operating hours reports achievable acres at the same capacity. These are operating-time relationships; weather delays or transport outside the supplied efficiency need separate planning.
How do fuel and hourly costs enter the estimate?
Enter fuel consumption in liters per operating hour and optional price per liter. Other hourly cost is separate. Divide their combined hourly rate by effective capacity for cost per acre, and multiply by project operating hours for the scoped subtotal.
How can you compare speeds or implement widths?
Save a scenario, then change width, overlap or supported work speed and compare effective capacity and project time. Keep efficiency assumptions visible. A faster travel speed is only useful if it remains suitable for the work and achieved operating conditions.
Which tools help plan the lawn materials afterward?
Use the Grass Seed Calculator for product mass and the Sod Calculator for turf coverage. Acreage per hour describes work capacity, not the material application rate.
